| Number | 351
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| Category | errata
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| Synopsis | 9.2.2, Example 7: unclear comment
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| State | lrmdraft
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| Class | errata-simple
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| Arrival-Date | May 26 2003
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| Originator | Shalom Bresticker <Shalom.Bresticker@motorola.com>
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| Release | 2001b: 9.2.2, Example 7
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| Environment |
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| Description |
In 9.2.2, Example 6, there is code initial begin // starts at time 0, does not hold the block r1 = 0 ; // makes assignments to r1 without cancelling previous assignments for (i=0; i <= 5; i=i+1) r1 <= #(i*10) i[0] ; end The first comment is unclear, particularly "does not hold the block". It is an inheritance from Cadence LRM, but it is not clear there, either. I suggest to delete the first comment entirely. Also, it is unclear to me why the line "r1 = 0;" was added. The example seems to work even without it. However, there is no need to delete it. -- Shalom Bresticker Shalom.Bresticker@motorola.com Design & Reuse Methodology Tel: +972 9 9522268 Motorola Semiconductor Israel, Ltd. Fax: +972 9 9522890 POB 2208, Herzlia 46120, ISRAEL Cell: +972 50 441478 |
| Fix |
In 9.2.2, Example 7: module multiple4; reg r1; reg [2:0] i; initial begin // starts at time 0, does not hold the block r1 = 0; // makes assignments to r1 without cancelling previous assignments for (i = 0; i <= 5; i = i+1) r1 <= # (i*10) i[0]; end endmodule DELETE the lines "// starts at time 0, does not hold the block r1 = 0; " |
| Audit-Trail |
Fix replaced by Shalom.Bresticker@freescale.com on Sun Oct 31 23:55:13 2004 In 9.2.2, Example 7: module multiple4; reg r1; reg [2:0] i; initial begin // starts at time 0, does not hold the block r1 = 0; // makes assignments to r1 without cancelling previous assignments for (i = 0; i <= 5; i = i+1) r1 <= # (i*10) i[0]; end endmodule DELETE the lines "// starts at time 0, does not hold the block r1 = 0; " |
| Unformatted |
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